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The height of a triangle is twice the length of its base. The area of the triangle is 50m^2. Find the height and base to the nearest tenth of a meter

Respuesta :

[tex]A = 50m^2 h = 2b[/tex]

[tex]A = \frac{1}{2}bh [/tex]

[tex]A = \frac{1}{2} b(2b)[/tex]

[tex]50 = \frac{2b^2}{2} b^2 = 50 b = 5 \sqrt{2} = 7.1 m h = 2b = 2(5 \sqrt{2}) = 10 \sqrt{2} = 14.1 m[/tex]

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