Respuesta :

kenmyna
 The  number  of atoms in 1.00 grams  of Ag  is calculated as  below

calculate  the moles of Ag = mass/molar mass

=  1g/ 107.87 g/mol= 9.27 x10 ^-3  moles

by use  of Avogadro law  constant 1 mole = 6.02 x10^23 atoms

what  about 9.27 x10 ^-3  moles

= (9.27 x10^-3 moles/ 1mole) x6.02 x10 ^23  atoms  = 5.581  x10^ 21 atoms

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