Respuesta :

carlosego
 For this case we have the following system of equations:
 [tex]5x + 60y = 35 x + y = 1.5[/tex]
 Where,
 x: time in hours walking
 Y: time in hours on the bus
 We solve the system of equations.
 Rewriting the system we have:
 [tex]5x + 60y = 35 -60x -60y = -90[/tex]
 Adding both equations we have:
 [tex]-55x = -55 [/tex]
 Clearing x we have:
 [tex]x = -55 / -55 x = 1[/tex]
 Then, the number of Yochanan road miles is:
 [tex]5x = 5 (1) = 5 [/tex]
   Answer:
   Yochanan walked about:
   5 miles

Answer:

The distance Yochanan covered by walking is 5 miles.

Step-by-step explanation:

Given: The system of equations

5x + 60y = 35

and x + y = 1.5

We have to determine the distance Yochanan covered by walking.

Consider the given system of linear equation.

5x + 60y = 35

and x + y = 1.5

Where x represents the time he takes to cover walking distance.

and y represents the time taken by school bus.

We need to find x,

Consider the system

5x + 60y = 35   ...........(1)

x + y = 1.5   ..........(2)

Using elimination method to solve the given system.

Multiply equation (2) by 60

(2) ⇒  60x + 60y = 90 ..........(3)

Subtract (1) from (3) , we have,

60x + 60y -(5x+ 60 y ) = 90 - 35

⇒ 55x = 55

⇒ x = 1

Thus, He took 1 hours walking.

[tex]Speed=\frac{Distance}{time}[/tex]

Given : speed = 5 miles per hour

time = 1 hour

So, Distance = 5 miles per hour × 1 hour = 5 km.

Thus, The distance Yochanan covered by walking is 5 miles.

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