Answer:
Correct option is:
the quantity 3x minus 4y all over the quantity 4x plus 3y
Step-by-step explanation:
We have to simplify:
quantity x over 4 minus y over 3 all over the quantity x over 3 plus y over 4 can be written as:
[tex]\dfrac{\dfrac{x}{4}-\dfrac{y}{3}}{\dfrac{x}{3}+\dfrac{y}{4}}[/tex]
Which is equivalent to:
[tex]\dfrac{\dfrac{3x-4y}{12}}{\dfrac{4x+3y}{12}}[/tex]
which is equal to:
[tex]\dfrac{3x-4y}{4x+3y}[/tex]
Hence, the correct option is:
the quantity 3x minus 4y all over the quantity 4x plus 3y
