Let us assume the smallest of the three consecutive integers = x Then The middle integer among the three consecutive integers will be = x + 1 The biggest integer among the three consecutive integers will be = x + 2 The sum of the three consecutive integers is already given in the question and it is -165. Then x + x + 1 + x + 2 = - 165 3x + 3 = - 165 3x = - 165 - 3 3x = - 168 x = - (168/3) = - 56 So the integer that is closest to zero is - 56. This is the answer you were looking for hopefully. The other integers will obviously be at a greater distance from zero.
