Respuesta :
Answer:
Volume = 1.901 * 10^6 liters
Explanation:
We will assume that the pressure of the gas is kept constant.
Charles's law states that: "At constant pressure, the volume of a given mass of gas is directly related to its temperature in kelvin."
This means that:
V1 / T1 = V2 / T2
where:
V1 is the initial volume = 1.35 × 10^6 liters
T1 is the initial temperature = 11 + 273 = 284 degrees kelvin
V2 is the final volume that we want to find
T2 is the final temperature = 127 + 273 = 400 degrees kelvin
Substitute with the givens in the above equation to get the final volume as follows:
V1 / T1 = V2 / T2
(1.35 × 10^6) / (284) = V2 / (400)
V2 = 400 * [(1.35 × 10^6) / (284)]
V2 = 1.901 * 10^6 liters
Hope this helps :)
Volume = 1.901 * 10^6 liters
Explanation:
We will assume that the pressure of the gas is kept constant.
Charles's law states that: "At constant pressure, the volume of a given mass of gas is directly related to its temperature in kelvin."
This means that:
V1 / T1 = V2 / T2
where:
V1 is the initial volume = 1.35 × 10^6 liters
T1 is the initial temperature = 11 + 273 = 284 degrees kelvin
V2 is the final volume that we want to find
T2 is the final temperature = 127 + 273 = 400 degrees kelvin
Substitute with the givens in the above equation to get the final volume as follows:
V1 / T1 = V2 / T2
(1.35 × 10^6) / (284) = V2 / (400)
V2 = 400 * [(1.35 × 10^6) / (284)]
V2 = 1.901 * 10^6 liters
Hope this helps :)
From the Charle's law V1/T1=V2/T2
V1= 1.35 ×10^6 L
T1= 11 +273 = 284 K
T2 = 127+273 = 400 k
Therefore, V2 = V1T2/T1
= (1.35 ×10^6 × 400)/284
= 1.901 ×10^6 Liters
V1= 1.35 ×10^6 L
T1= 11 +273 = 284 K
T2 = 127+273 = 400 k
Therefore, V2 = V1T2/T1
= (1.35 ×10^6 × 400)/284
= 1.901 ×10^6 Liters