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you suspend a brass ring from a spring scale. Its weight is 0.83 n while it is suspended in air. Next, you immerse the ring in a container of light corn syrup. The ring appears to weight 0.71 N. What is the buoyant force acting on the ring?

Respuesta :

     Using the Newton's Secound Law in the first situation, we have:

[tex]P-F=ma \\ P=0.83N[/tex]
 
     Applying the same formula in the secound situation:

[tex]P-E=F \\ 0.83-0.71=E \\ \boxed {E=0.12N}[/tex]

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