Respuesta :
average rate of reaction of H2 over this time is calculated as
initial concentration of H2 minus final concentration of H2
That is
{(0.35mol/l -0.12mol/l) / 50 sec}= 4.6 x 10 ^-3 mol/l/sec
initial concentration of H2 minus final concentration of H2
That is
{(0.35mol/l -0.12mol/l) / 50 sec}= 4.6 x 10 ^-3 mol/l/sec
1) Balanced chemical reaction: 3H₂ + N₂ → 2NH₃.
c₁(H₂) = 0.35 mol/L; initial concentration of hydrogen gas.
c₂(H₂) = 0.12 mol/L; concentration of hydrogen after 50 seconds.
Δt = 50 s.
the average rate of reaction = 1/3 · (Δc(H₂)/Δt).
the average rate of reaction of hydrogen = 1/3 · ((c₂(H₂)-c₁(H₂))/Δt).
the average rate of reaction = 1/3 · (0.12 mol/L - 0.35 mol/L) / 50 s.
the average rate of reaction of hydrogen = -0.00153 mol/Ls, it is negative because it measures the rate of disappearance of the reactants.
2) From chemical reaction: n(H₂) : n(NH₃) = 3 : 2.
c(NH₃) = 2 · 0.23 mol/L / 3.
c(NH₃) = 0.153 mol/L.
the average rate of reaction of ammonia = 1/2 · (0.153 / 50 s).
the average rate of reaction of ammonia = 0.00153 mol/L·s.