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A vertical spring 0.100 meter long is elongated to a length of -.119 meter when a 1.00 kilogram mass is attached to the bottom of the spring. the spring constant of this spring is

Respuesta :

carlosego
By definition we have that the force of the spring is given by:
 F = -k * deltax
 Where,
 k: spring constant
 deltax = elongation
 Let's clear k:
 k = -F / delta x
 k = mg / delta x
 delta x = 0.119 -0.1 = 0.019m
 Substituting the values:
 k = (1) * (9.81) / (. 019)
 k = 516 N / m
 Answer:
 the spring constant of this spring is
 k = 516 N / m
hamzaahmeds

This question involves the concepts of the spring constant, elongation, and force.

The spring constant of this spring is "516.3 N/m".

SPRING CONSTANT

The spring constant can be given by the following formula:

[tex]F=kx\\\\k =\frac{F}{x}[/tex]

where,

  • k = spring constant = ?
  • F = Force applied = Weight = mg = (1 kg)(9.81 m/s²) = 9.81 N
  • x = elongation of spring = 0.119 m - 0.1 m = 0.019 m

Therefore,

[tex]k=\frac{9.81\ N}{0.019\ m}[/tex]

k = 516.3 N/m

Learn more about spring constant here:

https://brainly.com/question/4291098