Respuesta :
Because we are finding the lowest point of the rope we have to minimize the equation h=0.01x2-x+27. We first have to find the derivative of the equation which would be h’=0.02x-1 then find the value of x when h’=0, which is x=50. Using this value to substitute for x in the original equation, we find that the lowest point of the rope is only 2 inches above ground.