Maria’s starting wage for her new job is $8.50 per hour. Each month during her first year, her hourly wage will increase by $0.50. What will her hourly wage be in her 10th month on the job?

Respuesta :

Answer: $13

Step-by-step explanation:

Given: The starting wage for Maria's new job =$8.50 per hour.

Also, Each month during her first year, her hourly wage will increase by $0.50.

Then, her hourly wage in second month =[tex]\$(8.50+0.50)[/tex]

Her hourly wage in third month =[tex]\$(8.50+2(0.50))[/tex]

Similarly, her hourly wage for nth month =[tex]\$(8.50+(n-1)(0.50))[/tex]

Thus, her hourly wage for 10th month =[tex]\$(8.50+(10-1)(0.50))[/tex]

=[tex]\$(8.50+(9)(0.50))=\$13[/tex]

Hence, her hourly wage be in her 10th month on the job = $13

Maria's hourly wage for 10th month is $13.

The starting wage for Maria's new job is $8.50 per hour.

Each month during her first year, her hourly wage will increase by $0.50.

Now her hourly wage in second month =[tex]8.50+0.50= $9[/tex]

Her hourly wage in third month = [tex]9+0.5=9.5[/tex]

So, total increase in her hourly wage after 9 month = [tex]0.5\times 9=4.5[/tex]

 Maria's hourly wage for 10th month = [tex]8.5+4.5=13[/tex]

Hence Maria's hourly wage for 10th month is $13.

For more details on Unitary method follow the link below:

https://brainly.com/question/12116123