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How many atoms of each element are in 4Na3PO4?

A. 3 sodium, 1 phosphorus, 4 oxygen
B. 4 sodium, 4 phosphorus, 4 oxygen
C. 12 sodium, 1 phosphorus, 4 oxygen
D. 12 sodium, 4 phosphorus, 16 oxygen

Respuesta :

One mole of [tex]Na_{3}PO_{4}[/tex] consist of three atoms of sodium, one atom of phosphorus and four atoms of oxygen.

Now, according to question four moles of [tex]Na_{3}PO_{4}[/tex] is present. Therefore, every element present in the compound is multilply by four with their number of atoms in the compound.

So, Number of atoms of sodium in four moles of [tex]Na_{3}PO_{4}[/tex] is [tex]3\times 4[/tex] = 12 atoms of sodium.

Number of atoms of phosphorus in four moles of [tex]Na_{3}PO_{4}[/tex] is [tex]1\times 4[/tex] = 4 atoms of  phosphorus.

Number of atoms of oxygen in four moles of [tex]Na_{3}PO_{4}[/tex] is [tex]4\times 4[/tex] = 16 atoms of oxygen.

Hence, number of atoms of sodium is 12 , number of atoms of phosphorus is 4 and number of atoms of oxygen is 16

Thus, option (D) is the correct answer.



OlanmaE

The mole is a term used to describe the amount of a substance whereas the atom is the smallest indivisible particle of an element. In the question given the correct number of atoms of each of the elements is;

  • D. 12 sodium, 4 phosphorus, 16 oxygen

In this compound, it is important to note that the individual elements would first be accounted for.

This indicates the mole. Next, the number 4 affects all elements in the compound. Therefore, 4 will be used to multiply the individual elements.

4Na₃ =  (4 × 3) 12 atoms of sodium

P = (4 × 1) 4 atoms of Phosphorous

O₄ = (4 × 4) 16 atoms of oxygen.

Given this format, the atoms of the elements are identified.

Learn more here:

https://brainly.com/question/18311376

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