Respuesta :

x - distance between Jie and Xiaoqing.

[tex]\dfrac{x}{24\sqrt{5}}=\sin30^\circ\\\\\\\dfrac{x}{24\sqrt{5}}=\dfrac{1}{2}\qquad\qquad\qquad\text{(cross multiply)}\\\\\\2x=24\sqrt{5}\quad|:2\\\\x=12\sqrt{5}\\\\\boxed{x\approx26.83}[/tex]