Calculate the molarity of a solution made by putting 55.8 g of nano3 into a beaker and diluting to 2.50 l.

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01-12-2017
Chemistry

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Calculate the molarity of a solution made by putting 55.8 g of nano3 into a beaker and diluting to 2.50 l.

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andriansp andriansp · Answer 1 · 2017-12-11T11:54:02+01:00

If the molar weight of NaNO3 is 85g/mol, then the amount of molecule in this question would be: 55.8g/ (85g/mol)= 0.656 moles. The NaNO3 is solved by 2.5 l of water. Molarity is a unit of concentration of a solution that using unit moles of molecule per liter. The concentration/molarity of the solution would be:

concentration= number of moles / volume
concentration= 0.656 moles/ 2.5l= 0.26 molar

BarrettArcher BarrettArcher · Answer 2 · 2018-11-15T06:31:22+01:00

Answer : The molarity of a solution is 0.263 mole/L.

Solution : Given,

Mass of [tex]NaNO_3[/tex] = 55.8 g

Volume of solution = 2.50 L

Molar mass of [tex]NaNO_3[/tex] = 84.99 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

[tex]\text{ number of moles solute}=\frac{\text{ Given mass of solute}}{\text{ Molar mass of solute}}[/tex]

[tex]Molarity=\frac{w}{MV}[/tex]

where,

w = mass of solute

M = molar mass of solute

V = volume of solution

Now put all the given values in above formula of molarity, we get

[tex]Molarity=\frac{55.8g}{(84.99g/mole)\times (2.50L)}=0.263mole/L[/tex]

Therefore, the molarity of a solution is 0.263 mole/L.