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The five interior angles in a  pentagon are in the ratio 2:3:4:5:6. What is the measure of the pentagon's largest angle?

Respuesta :

Muks
Let All angles be x times multiplied to ratio , so we"ll get :-

2x + 3x + 4x + 5x + 6x = 540°

20x = 540

x = 540/20

⇒ x = 27 ,

so angles are :-

⇒ 2x = 2×27 = 54°

⇒ 3x = 3×27 = 81°

⇒ 4x = 4×27 = 108°

⇒ 5x = 5×27 = 135°

⇒ 6x = 6×27 = 162°

Hence 162° is the greatest angle

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