Answer:
Orbital period of the planet is 0.537 years.
Explanation:
Given that,
A planet has an average distance to the sun of 0.66 AU, [tex]a=0.66\ AU=9.87\times 10^{10}\ m[/tex]
The orbital period of the planet is determined using Kepler's law of planetary motion. Mathematically, the Kepler's law is given by :
[tex]T^2=\dfrac{4\pi^2}{GM}a^3[/tex]
[tex]T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 1.98\times 10^{30}}\times (9.87\times 10^{10})^3[/tex]
[tex]T=\sqrt{2.87\times 10^{14}}\ s[/tex]
T = 16941074.34 s
or
T = 0.537 years
So, the orbital period of the planet is 0.537 years. Hence, this is the required solution.
