Answer:
[tex]y=\frac{1}{4}x-4[/tex]
Step-by-step explanation:
we have
[tex]2x-8y=32[/tex] -----> equation of the line in standard form
we know that
the equation of the line into slope intercept form is equal to
[tex]y=mx+b[/tex]
where
m is the slope
b is the y-intercept
Convert the equation into slope intercept form
isolate the variable y
Adds [tex]8y[/tex] both sides
[tex]2x-8y+8y=32+8y[/tex]
[tex]2x=32+8y[/tex]
Subtract [tex]32[/tex] both sides
[tex]2x-32=32+8y-32[/tex]
[tex]2x-32=8y[/tex]
Divide by [tex]8[/tex] both sides
[tex](2x-32)/8=8y/8[/tex]
[tex](2x-32)/8=y[/tex]
Rewrite
[tex]y=\frac{1}{4}x-4[/tex] -----> equation of the line into slope intercept form
