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Ten identical slips of paper each contain one number from one to ten, inclusive. The papers are put into a bag and then mixed around.
Which statements about the situation are true? Check all that apply.
P(6) = P(1)
P(5) =
P(>10) = 0
P(1 < x < 10) = 100%
S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
If A ⊂ S; A could be {1, 3, 5, 7, 9}

Respuesta :

For E2020 users, the correct answer is A, C, E, F.
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By analyzing the given experiment, we will see that the statements are:

  • 1) True
  • 2) incomplete statement, we can't say.
  • 3) True
  • 4) False
  • 5) True.
  • 6) True.

Working with probabilities of random selection.

Here we assume that all the papers have the same probability of being randomly drawn from the bag.

This means that:

P(1) = P(2) = ... = P(10) = 1/10

Where:

P(n) = probability of randomly getting the paper with number n.

Now, let's see which statements are true.

1) P(6) = P(1)

This one is true, all the papers have the same probability of being drawn.

2) P(5) =

This statement is incomplete sadly, so we can't say.

3) P(>10) = 0

True, as the largest number in the papers is 10, is impossible to get a value larger than 10.

4) P(1 < x < 10) = 100%

This is false, because in that case the values x = 1 and x = 10 are not counted, so the probability can't be equal to the 100%.

5) S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

True, this is the sample space, all the possible outcomes.

6) If A ⊂ S; A could be {1, 3, 5, 7, 9}

A ⊂ S means that S contains set A, so set A is only formed from elements from set S.

And in the given example all the elements belong to the set S, so this is true.

If you want to learn more about probabilities, you can read:

https://brainly.com/question/251701

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