Respuesta :

3x + 1 < 7...subtract 1 from both sides
3x < 7 - 1
3x < 6 ...divide both sides by 3
x < 6/3
x < 2

there will be an open circle on 2....because the problem has no equal sign...the line will be shaded to the left...because it is less then.

The solution of the inequality [tex]3x + 1 < 7[/tex] is [tex]\boxed{x < 2}.[/tex]

Further explanation:

There are two types of the interval close interval and open interval.

If the values of [tex]\text{x}[/tex] doesn’t includes the number than it is represented by hollow dot on the number line and if the values of [tex]\text{x}[/tex] includes the number than it is represented by the solid dot on the number line.

Given:

The inequality is [tex]3x + 1 < 7.[/tex]

Explanation:

The given inequality is [tex]3x + 1 < 7.[/tex]

Subtract 1 from both side of the inequality.

[tex]\begin{aligned}3x + 1 - 1 &< 7 - 1\\3x &< 6\\\end{aligned}[/tex]

Now divide both sides by 3.

[tex]\begin{aligned}\frac{{3x}}{3} &< \frac{6}{3}\\x&< 2\\\end{aligned}[/tex]

The solution of the inequality [tex]3x + 1 < 7[/tex] is [tex]\boxed{x < 2}.[/tex]

Learn more:

  1. Learn more about inverse of the function https://brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function https://brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Compound inequalities

Keywords: solution, [tex]3x + 1 < 7[/tex], inequalities, graph, compound inequality, graph representation, number line, close interval, open interval, line graph.