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What is the approximate mass of 25 cm3 of silver, if the density is 10.5 g/cm3?
a.0.42 g
b.2.4 g
c.42 g
d.260 g

Respuesta :

WafiqAhmed
25 x 10.5 = 262.5

So the approx. is 260 g which is answer D.

Answer:

Mass, m = 260 grams

Explanation:

It is given that,

Density of silver, [tex]d=10.5\ g/cm^3[/tex]

Volume of the silver, [tex]V=25\ cm^3[/tex]

We need to find the mass of a piece of silver. The formula for the density is given by :

[tex]d=\dfrac{m}{V}[/tex]

[tex]m=d\times V[/tex]

[tex]m=10.5\ g/cm^3\times 25\ cm^3[/tex]

m = 262.5 g

or

m = 260 grams

So, the mass of the piece of the silver is 260 grams. Hence, this is the required solution.

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