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Aqueous solutions of sodium thiosulfate, na2s2o3, are used as an antidote to some snakebites. how many moles of sodium ions are found in 10.0 ml of a 0.15 m solution of na2s2o3?

Respuesta :

When Na2S2O3 dissolves in water, it dissociates into Na+ and S2O32- ions:
Na2S2O3 ⇒2Na+ + S2O32-

So 1 mole of Na2S2O3 generates 2 Na+s.

The moles of Na2S2O3 = volume of Na2S2O3 * molarity of Na2SO3 = 0.01L * 0.15mol/L = 0.0015 mol.

Therefore, the moles of Na+ in the solution = 0.0015mol * 2 = 0.003 mole.

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