Answer:
The numbers are 30,36,42,48.
Step-by-step explanation:
Given : Four consecutive multiples of 6 yield a sum of 156.
To find : What are these multiples?
Solution :
Let the first consecutive multiples of 6 be 'x'.
The second consecutive multiples of 6 be 'x+6'.
The third consecutive multiples of 6 be 'x+12'.
The fourth consecutive multiples of 6 be 'x+18'.
Now, their sum is 156
i.e. [tex]x+(x+6)+(x+12)+(x+18) = 156[/tex]
[tex]4x +30 = 156[/tex]
[tex]4x = 120[/tex]
[tex]x=\frac{120}{4}[/tex]
[tex]x=30[/tex]
The first number is 30.
The second number is 30+6=36
The third number is 30+12=42
The fourth number is 30+18=48
Therefore, the numbers are 30,36,42,48.
