contestada

A 55-mL solution of H2SO4 is completely neutralized by 46 mL of 1.0M NaOH. What is the concentration of the H2SO4∆H2SO4(aq) +2NaOH(aq) → Na2SO4(aq) + 2H2O(l)

Respuesta :

H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O

v(NaOH)=46 ml=0.046 l
c(NaOH)=1.0 mol/l
v(H₂SO₄)=55 ml=0.055 l

n(NaOH)=v(NaOH)*c(NaOH)

n(H₂SO₄)=0.5n(NaOH)

c(H₂SO₄)=n(H₂SO₄)/v(H₂SO₄)=0.5*v(NaOH)*c(NaOH)/v(H₂SO₄)

c(H₂SO₄)=0.5*0.046*1.0/0.055=0.418 mol/l

The concentration of the H₂SO₄ is 0.418M.

Otras preguntas