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The initial temperature of a bomb calorimeter is 28.50°
c. when a chemist carries out a reaction in this calorimeter, its temperature decreases to 27.45°
c. if the calorimeter has a mass of 1.400 kg and a specific heat of 3.52 j/(gi°
c., how much heat is absorbed by the reaction?

Respuesta :

The answer is 5,170 J
martinbrusconi

Answer:

The answer is 5174400 J.

Explanation:

Here you have to keep in mind the equation to determine the amount of heat  (Q) that one body of mass m can take. The equation is : [tex] Q=mc\Delta T [\tex]

where m is the mass, c is the specific heat and [tex] \Delta T [\tex] the temperature variation. This way: Q=1400kg*3.52J/gºC*(28.5-27.45) ºC=1400000 g*3.52 J/gºC * (28.5-27.45)ºC=5174400J=5174.4 kJ=5.17 MJ.

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