Answer : The specific heat of aluminum is, [tex]0.90J/g^oC[/tex]
Solution : Given,
Heat absorbs = 677 J
Mass of the substance = 10 g
Final temperature = [tex]125^oC[/tex]
Initial temperature = [tex]50^oC[/tex]
Formula used :
[tex]Q= m\times c\times \Delta T[/tex]
or,
[tex]Q= m\times c\times (T_{final}-T_{initial})[/tex]
Q = heat absorbs
m = mass of the substance
c = heat capacity of aluminium
[tex]T_{final}[/tex] = final temperature
[tex]T_{initial}[/tex] = initial temperature
Now put all the given values in the above formula, we get the specific heat of aluminium.
[tex]677g= (10g)\times c\times (125-50)^oC[/tex]
[tex]c=0.9026J/g^oC=0.90J/g^oC[/tex]
Therefore, the specific heat of aluminum is, [tex]0.90J/g^oC[/tex]
