contestada

What is the area of a sector with a central angle of 2π9 radians and a diameter of 20.6 mm?

Use 3.14 for π and round your answer to the nearest hundredth.

Respuesta :

A=(2x3.14/9/2) 10.3^2
37.013622 rounded to nearest hundredth is 37.01

Answer:

[tex]37.01\ mm^{2}[/tex]

Step-by-step explanation:

we know that

The area of a circle is equal to

[tex]A=\pi r^{2}[/tex]

we have

[tex]r=20.6/2=10.3\ mm[/tex] ----> the radius is half the diameter

substitute

[tex]A=(3.14)(10.3^{2})=333.1226\ mm^{2}[/tex]

[tex]2\pi[/tex] radians subtends the complete circle of area [tex]333.1226\ mm^{2}[/tex]

so

by proportion

Find the area of  a sector with a central angle of [tex]2\pi/9[/tex] radians

[tex]\frac{333.1226}{2\pi}=\frac{x}{2\pi/9}\\ \\x=336.1226*( 2\pi/9)/(2\pi)\\ \\x=37.01\ mm^{2}[/tex]