A solution is prepared by mixing 20.0 g of NaNO3 with 100. mL of water. What is the percentage mass of the solution?

Percentage by mass is the amount of a component in a mixture per 100 unit if mass of the total mixture. From the problem, we first need to convert the volume of water to mass by using the density of water of 1000 g/L. We calculate as follows:

Mass of water = .100 L ( 1000 g/L ) = 100 g water
Total mass = 100 g + 20 g = 120 g

Percent mass = 20 / 120 x 100 = 16.67% NaNO3 solution

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Abdulazeez10 Abdulazeez10 · Answer 2 · 2022-03-17T14:29:57+01:00

The percentage mass of the solution is 16.67%

Percentage mass

From the question, we are to determine the percentage mass of the solution

First, we will determine the mass of the solvent (water)

Volume of water = 100 mL = 100 g

NOTE: For water, 1 g = 1 mL

Now, for the percentage mass of the solution

[tex]Percentage\ mass\ of\ the\ solution = \frac{Mass\ of\ solute}{Mass\ of\ solution} \times 100\%[/tex]

Mass of solute = 20.0 g

Mass of solution = 20.0 g + 100g = 120.0 g

Then,

[tex]Percentage\ mass\ of\ the\ solution = \frac{20.0}{120.0} \times 100\%[/tex]

Percentage mass of the solution = 16.67%

Hence, the percentage mass of the solution is 16.67%

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