For the following equation (2NaOH+H2SO4--->Na2So4+2H2O) what mass of sodium sulfate (in grams) will be produced from 1.85 mold of sodium hydroxide,NAOH?
number of mole (NaOH)= 1.85 mol Using mole ratio n(Na2SO4)/n(NaOH)= 1/3 So number of mole of Na2SO4 is the number of mole of NaOH multiplied by 1/3 which equals 0.616 (approx.) Then to find mass we use Mass(in grams)= number of mole of compound (Na2SO4) multiplied by the Molar mass of our compound molar mass (Na2SO4) =142.04 m= n X Mr m= 0.616 x 142.04 =87.59g