Respuesta :
The initial potassium hydroxide solution has a molarity of 0.57M.
Step 1: Acidic HNO3 + KOH Solution
To locate nitric acid moles:
(1.12 mol/L x (0.0468 L) = 0.052 mol HNO3
To locate KOH moles:
KOH's molarity is determined by the formula (0.0279 L)(x) = 0.0279x mol KOH.
Although we are unable to precisely calculate the moles of KOH added, we do know that adding basic KOH to acidic HNO3 still produces an acidic solution, indicating that about 0.052 moles of KOH were added. To completely neutralize the 0.052 mol of acid, step 2 will add the last moles of -OH.
Step 2: Ba neutralizes the Solution (OH)
2
[tex]Ba(OH)_{2}[/tex] mole detection:
0.018 mol [tex]Ba(OH)_{2}[/tex] is equal to (0.0190 L)(0.968mol/L).
To calculate the moles of -OH in 0.018 mol of Ba(OH)
2 0.018 mol Ba (OH)
0.036 mol -OH is equal to 2 times (2 mol -OH / 1 mol [tex]Ba(OH)_{2}[/tex]).
It is neutralized in this stage. Remember that by incorporating 1 mol of [tex]Ba(OH)_{2}[/tex], we actually incorporate 2 molar equivalents of -OH. We attain neutralization after 0.036 mol of -OH has been added.
Neutralization: The formula is (moles of HNO3) - (moles of -OH)
= 0 (0.052 mol) - (0.0279x + 0.036)
= 0 0.016 = 0.0279x
x = 0.57 M.
To learn more about molarity, refer:-
https://brainly.com/question/8732513
#SPJ4
