It is given that the satisaction is 72% so p=0.72 and 5 people are chosen at random so n=5.
Part a:The probability distribution is given by:
Part b:The mean is given by:
[tex]\mu=np=0.72\times5=3.6[/tex]Part c: The standard deviation is given by:
[tex]\sigma=\sqrt[]{npq}=\sqrt[]{5\times0.72\times0.28}=1.00399\approx1.004[/tex]