Twice a number added to 6 is less than 23
[tex]2x+6<23[/tex]is 10 a possible solution. ?
In order to answer this question, we must solve for x
[tex]\begin{gathered} 2x+6<23 \\ 2x+6-6<23-6 \\ 2x<17 \\ \frac{2x}{2}<\frac{17}{2} \\ x<\frac{17}{2} \\ x<8.5 \end{gathered}[/tex]the solution is all numbers less than 8.5, therefore 10 is not a possible solution.
