By assuming that the rate is constant and the speed is given by
[tex]\text{speed = }\frac{dis\tan ce}{time}[/tex]we have that
[tex]0.25\frac{m}{s}=\frac{d}{240s}[/tex]because 4 minutes is equal to 240 seconds. Then, the distance is given as
[tex]\begin{gathered} d=(0.25\frac{m}{s})(240s) \\ d=60\text{ m} \end{gathered}[/tex]Therefore, the depth of the swimmer will be 60 meters plus 0.5 meters. Then, the answer is -60.5 meters (option A)
