we have the line
7x-8y=-1
Find out the slope of the given line
isolate the variable y
8y=7x+1
y=(7/8)x+1/8
the slope is m=7/8
Part a
Find the equation of the line that is parallel to this line and passes through the point . (-3,-6)
Remember that
If two lines are parallel, then their slopes are equal
so
The slope of the parallel line is m=7/8 too
Find out the equation of the line in slope-intercept form
y=mx+b
we have
m=7/8
point (-3,-6)
substitute and solve for b
-6=(7/8)(-3)+b
b=-6+(21/8)
b=-27/8
therefore
The equation is
y=(7/8)x-27/8
Part b
Find the equation of the line that is perpendicular to this line and passes through the point . (-3.-6)
Remember that
If two lines are perpendicular, then their slopes are negative reciprocal
so
The slope of the perpendicular line is m=-8/7
Find out the equation of the line in slope-intercept form
y=mx+b
we have
m=-8/7
point (-3,-6)
substitute and solve for b
-6=-(8/7)(-3)+b
b=-6-(24/7)
b=-66/7
therefore
the equation is
y=-(8/7)x-66/7
