In this problem we know that the initial velocity in the horizontal axis is 25, however the initial velocity in the y axis will be o so we can use this equation:
[tex]y=y_0+v_it+\frac{1}{2}at^2[/tex]So to find the time the object get the grownd we can replace the initial high for 5 miter, the final one for 0 and the aceleration by -9.8 (gravity) so:
[tex]0=5+0(t)+\frac{1}{2}(-9.8)t^2[/tex]and we solve for t so:
[tex]\begin{gathered} 9.8t^2=5\cdot2 \\ t^2=\frac{10}{9.8} \\ t\approx\sqrt[]{1} \\ t\approx1 \end{gathered}[/tex]So the projectil takes one secon to hit the grownd
