Given:
As angle N is 90 degree.
[tex]\begin{gathered} \angle N=44^{\circ}+\angle n \\ \angle n=90^{\circ}-44^{\circ} \\ \angle n=46^{\circ} \end{gathered}[/tex]
To find the bearing of flight from Elgin to Canton.
Use the sin ratio,
[tex]\begin{gathered} \frac{\sin c}{510}=\frac{\sin n}{720} \\ \frac{\sin c}{510}=\frac{\sin46^{\circ}}{720} \\ \sin c=\frac{\sin46^{\circ}}{720}\times510 \\ \sin c=0.4995 \\ c=\sin ^{-1}(0.5095) \\ c=30.63^{\circ} \end{gathered}[/tex]
The bearing angle ( clockwise from north ) can be calculated by subtracting the above angle from the west bearing angle of 270 degree.
[tex]270^{\circ}-30.63^{\circ}=239.37^{\circ}[/tex]
Answer: 239.37 degree
