The slope-intercept form of the equation of a straight line is given to be:
[tex]y=mx+b[/tex]where m is the slope and b is the intercept on the y-axis.
The slope is calculated using two points on the line by the formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Therefore, for this line, the slope will be:
[tex]m=\frac{4-0}{3-6}=-\frac{4}{3}[/tex]Therefore, this value for the slope is substituted back into the equation for the line:
[tex]y=-\frac{4}{3}x+b[/tex]At the point (6, 0), we can calculate the value of b to be:
[tex]\begin{gathered} 0=-\frac{4}{3}(6)+b \\ b=\frac{4}{3}(6) \\ b=8 \end{gathered}[/tex]Therefore, the equation is:
[tex]y=-\frac{4}{3}x+8[/tex]