Given that the radius of the circular path is r = 142 m and the coefficient of the friction is
[tex]\mu=1.07[/tex]The condition for the car to travel safely is
Frictional force = centrifugal force
[tex]\mu mg=\frac{mv^2}{r}[/tex]Here, m is the mass of the car and the acceleration due to gravity is g = 9.8 m/s^2.
v is the maximum speed of the car.
[tex]\begin{gathered} v=\sqrt[]{ugr} \\ =\sqrt[]{1.07\times9.8\times142} \\ =38.58\text{ m/s} \end{gathered}[/tex]