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On October 23, 2011, one U.S. dollar was worth 13.65 Mexican pesos.(a) On that date, how many pesos was 81.35 dollars worth?Round your answer to the nearest hundredth of a peso.pesos(b) On that date, how many dollars was 91.03 pesos worth?Round your answer to the nearest hundredth of a dollar.

Respuesta :

Solution

We are given that

[tex]\text{ \$}1=13.65\text{ }pesos[/tex]

a.

[tex]\begin{gathered} \text{ \$}81.35=81.35\times13.65\text{ }pesos \\ \\ \text{ \$}81.35=1110.43\text{ }pesos\text{ \lparen to the nearest hundredth\rparen} \end{gathered}[/tex]

b.

[tex]\begin{gathered} 1\text{ }pesos=\text{ \$}\frac{1}{13.65} \\ \\ 91.03pesos=\text{ \$}\frac{1}{13.65}\times91.03 \\ \\ 91.03pesos=\text{ \$}6.67\text{ \lparen to the nearest hundredth\rparen} \end{gathered}[/tex]

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