Recall that the quadratic formula states that the solution to the quadratic equation:
[tex]ax^2+bx+c=0[/tex]are:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.[/tex]Notice that a is the coefficient of the quadratic part, b is the coefficient of the linear part and c is a constant.
We can rewrite the given equation as follows:
[tex](-1)x^2+3x+(-7)=0.[/tex]Therefore, the values a, b, and c that should be used in the quadratic formula to compute the solutions to the quadratic equation:
[tex]-x^2+3x-7=0[/tex]are:
[tex]\begin{gathered} a=-1, \\ b=3, \\ c=-7. \end{gathered}[/tex]Answer:
[tex]\begin{gathered} a=-1, \\ b=3, \\ c=-7. \end{gathered}[/tex]