Given
The system of equations given are
[tex]\begin{gathered} y=-8x+10 \\ y=x-8 \end{gathered}[/tex]
Explanation
Solve the given system of equations using elimination method
[tex]\begin{gathered} y=-8x+10..........1 \\ y=x-8......2 \end{gathered}[/tex]
Subtract equation 1 by equation 2.
[tex]\begin{gathered} (y+8x-10)-(y-x+8)=0 \\ 8x-10+x-8=0 \\ 9x=18 \\ x=2 \end{gathered}[/tex]
Now find the value of y by substitute the value of x in equation 1.
[tex]\begin{gathered} y=-8\times2+10 \\ y=-16+10 \\ y=-6 \end{gathered}[/tex]
Answer
Hence the coordinates of x and y to the system of equations is
[tex](2,-6)[/tex]
