Given:
there are two types of tickets to a show: advance and same-day
Let the number of tickets from the type of Advance = x
And the number of tickets from the type of Same-day = y
there were 50 tickets sold in all
So,
[tex]x+y=50\rightarrow(1)[/tex]Advance tickets cost $30 and same-day tickets cost $15.
the total amount paid for them was $1275
So,
[tex]30x+15y=1275\rightarrow(2)[/tex]Solve the equations (1) and (2) to find (x) and (y)
[tex]\begin{gathered} x+y=50\rightarrow(\times-15) \\ 30x+15y=1275 \\ ============= \\ -15x-15y=-750 \\ 30x+15y=1275 \\ ============= \\ 15x=525 \\ x=\frac{525}{15}=35 \\ y=50-x=50-35=15 \end{gathered}[/tex]So, The answer will be:
The number of tickets from the type of Advance = x = 35
And the number of tickets from the type of Same-day = y = 15
