The equation of a line in slope-intercept form is;
[tex]y=mx+b[/tex]
For the given information, that is the slope and a point on the line, we now have;
[tex]\begin{gathered} (x,y)=(2,1) \\ m=-2 \\ y=mx+b\text{ now becomes;} \\ 1=-2(2)+b \\ 1=-4+b \\ \text{Add 4 to both sides} \\ 1+4=-4+4+b \\ 5=b \\ \text{Now that we have }\det er\min ed\text{ the value of b,} \\ We\text{ can substitute for m and b as follows; } \\ y=mx+b\text{ becomes;} \\ y=-2x+5 \end{gathered}[/tex]
ANSWER:
The equation of the line therefore is;
[tex]y=-2x+5[/tex]
