Respuesta :

Given the numbers:

[tex]3^{\frac{1}{3}},\text{ }4^{\frac{1}{2}},\text{ }\sqrt[3]{9},\text{ 1}^8,\text{ \lparen-}\frac{1}{2})^{-2}[/tex]

Let's arrange the numbers from the least to the greatest without the use of a calculator.

Now, let's first simplify each term.

We have:

[tex]\begin{gathered} 3^{\frac{1}{3}}=\sqrt[3]{3} \\ \\ 4^{\frac{1}{2}}=\sqrt{4}=2 \\ \\ \sqrt[3]{9} \\ \\ 1^8=1 \\ \\ -(\frac{1}{2})^{-2}=(-2)^2=4 \end{gathered}[/tex]

Therefore, arranging the numbers from the least to the greatest, we have:

[tex]\begin{gathered} 1 \\ \\ \\ 3^{\frac{1}{3}} \\ \\ \\ 4^{\frac{1}{2}} \\ \\ \sqrt[3]{9} \\ \\ \\ (-\frac{1}{2})^{-2} \end{gathered}[/tex]