Given the data:
36, 14, 18, 18, 34
Let's find the standard deviation of the sample distances.
To find the standard deviation, apply the formula:
[tex]S=\sum_{i\mathop{=}1}^n\sqrt{\frac{(x_i-x_{avg})^2}{n-1}}[/tex]
Where:
n = 5
Let's first find the average/,mean:
[tex]\begin{gathered} avg=\frac{36+14+18+18+34}{5} \\ \\ avg=\frac{120}{5} \\ \\ avg=24 \end{gathered}[/tex]
The mean of the sample is 24.
Now, to find the standard deviation, we have:
[tex]\begin{gathered} S=\sqrt{\frac{(36-24)^2+(14-24)^2+(18-24)^2+(18-24)^2+(34-24)^2}{5-1}} \\ \\ S=\sqrt{\frac{(12)^2+(-10)^2+(-6)^2+(-6)^2+(10)^2}{4}} \\ \\ S=\sqrt{\frac{144+100+36+36+100}{4}} \\ \\ S=\sqrt{\frac{416}{4}} \\ \\ S=\sqrt{104} \\ \\ S=10.20 \end{gathered}[/tex]
Therefore, the standard deviation of the given sample distances is 10.20
ANSWER:
10.20
