given the inequality
[tex]3x+2<−4\text{ }or\text{ }3x+3>27[/tex]
then
[tex]3x<−4-2\text{ }or\text{ }3x>27-3[/tex][tex]3x<−6\text{ }or\text{ }3x>24[/tex][tex]x<−2\text{ }or\text{ }x>8[/tex]
Graph:
notice the empty circle because the ineqaulity does not have equal symbol
interval:
[tex]\left(-\infty \:,\:-2\right)\cup \left(8,\:\infty \:\right)[/tex]
inequality:
[tex]x<-2\text{ }or\text{ }x>8[/tex]
