Solution
For this case we have the following data:
30, 40, 39, 36, 30
Representing the ages (in years) of the 5 doctors at a local clinic
these values represent an entire population, and we want to find the standard deviation of the population
1) First we need to calculate the mean
[tex]\mu=\frac{30+40+39+36+30}{5}=35[/tex]2) Now we can find the population variance like this:
[tex]\sigma^2=\frac{(30-35)^2+(40-35)^2+(39-35)^2+(36-35)^2+(30-35)^2}{5}=\frac{92}{5}=18.4[/tex]3) Calculate the population standard deviation
[tex]\sigma=\sqrt[]{18.4}=4.29[/tex]then the answer would be:
4.29
