B
For this problem Let's work in parts
1) Coin
Heads
Tails
Flipping the coin once, the Probability is:
[tex]P\text{ =}\frac{1}{2}[/tex]For there are two possible results, Heads or Tails, and there was one flipping.
2) Spinner
1 to 6 sections
The Probability of this spinner lands on a number lesser than 3
[tex]P\text{ =}\frac{2}{6}\text{ = }\frac{1}{3}[/tex]is 1 out of 3 for this spinner, since only 1, 2 are valid results.
So, the answer to this experiment
[tex]P\text{ = }\frac{1}{3}\cdot\frac{1}{2}\text{ = }\frac{1}{6}[/tex]Is the probability of both happen, both spinner and coin are 1 in six flipping. Since there are only two numbers < 3 on the spinner and two possibilities for the coin.
B
Heads, 1
Tails 1
Heads2
Tails 2
