Remember that
The volume of a cone is equal to
[tex]V=\frac{1}{3}\cdot\pi\cdot r^2\cdot h[/tex]we have
r=1/5 ft
pi=3.14
h=2 ft
substitute given values
[tex]\begin{gathered} V=\frac{1}{3}\cdot3.14\cdot(\frac{1}{5})^2\cdot2 \\ V=0.08\text{ ft3} \end{gathered}[/tex]