A ball is thrown vertically upward with a speed of 36.0 m/s.(a) How high does it rise? m(b) How long does it take to reach its highest point? s(c) How long does the ball take to hit the ground after it reaches its highest point? s(d) What is its velocity when it returns to the level from which it started? m/s

A ball is thrown vertically upward with a speed of 360 msa How high does it rise mb How long does it take to reach its highest point sc How long does the ball t class=

Respuesta :

ANSWER:

(a) 66.1 m

(b) 3.67 s

(c) 3.67 s

(d) -36 m/s

STEP-BY-STEP EXPLANATION:

Given:

Initial velocity (u) = 36 m/s

Final velocity (v) = 0 m/s

(a)

We can calculate the height using the following formula:

[tex]\begin{gathered} h=\frac{v^2-u^2}{2g} \\ \\ \text{ We replacing:} \\ \\ h=\frac{0^2-(36)^2}{(2)(-9.8)} \\ \\ h=66.1\text{ m} \end{gathered}[/tex]

(b)

Now, we calculate the time as follows:

[tex]\begin{gathered} v=u+gt \\ \\ t=\frac{v-u}{g} \\ \\ \text{ we replacing} \\ \\ t=\frac{0-36}{-9.8} \\ \\ t=3.67\text{ s} \end{gathered}[/tex]

(c)

The time it takes for the ball to hit the ground after reaching its highest point is the same as the time it takes to reach it, which means that it is equal to 3.67 seconds

(d)

The velocity it takes to return is also the same but being in the opposite direction, it has the same magnitude but with the opposite sign, that is, with a minus sign.

So the velocity when it returns to the level it started from is -36 m/s