Respuesta :
[tex]\frac{1}{3}[/tex]
Explanation
The probability of an event is the number of favorable outcomes divided by the total number of outcomes possible
Step 1
find the total of favorable possible
[tex]\begin{gathered} \text{for a dice, } \\ a\text{ number less than 5, it is, 1, 2, 3 or 4, ( 4 favorables outcomes}) \\ a\text{ number greater than 2, it is, 3,4 , 5 or 6} \\ \text{the numbers that have the two options are 3 and 4 ( 2 favorable outcomes)} \end{gathered}[/tex]favorable outcomes : 2 ( 3 and 4)
Step 2
find the total number of outcomes possilbe
the dice has 6 faces, (numbers, 1, 2, 3, 4, 5 or 6),
possible outcomes : 6 ( 1,2,3,4,5 and 6)
Step 3
finally replace
[tex]\begin{gathered} P=\frac{favorable\text{ outcomes}}{\text{possible outcomes}} \\ P=\frac{2}{6}=\frac{1}{3} \end{gathered}[/tex]